# What is the vertex of  y= -x^2 + 12x + 36?

Mar 28, 2016

$\left(6 , 72\right)$

#### Explanation:

$y = - {\left(x - 6\right)}^{2} + 72$
graph{-(x-6)^2 + 72 [-20, 20, -80, 80]}
The vertex is the topmost point of the parabola.

Maximum occurs when $x = 6$, and $y = 72$.

The vertex is $\left(6 , 72\right)$.