What is the vertex of #y=x^2-2x+1+(x-3)^2 #?

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Answer 1 · 2018-04-11T17:23:58

#(2,2)#

Let's simplify the expression,

#" "y=x^2-2x+1+x^2+9-6x#

#=>" "y=2x^2-8x+10#

#=>" "y/2-1=x^2-4x+4#

#=>" "1/2(y-2)=(x-2)^2#

This is the equation of standard parabola of the form #x^2=4ay#

The origin is shifted and so the new vertex is #(2,2)#