# What is the vertex of # y=-x^2 - 2x - 3(x/3-2/3)^2 #?

##### 1 Answer

#### Answer

#### Answer:

#### Explanation

#### Explanation:

#### Answer:

Hence, the vertex is

I have approached by the method of calculus (maxima and minima)

#### Explanation:

I have approached by the method of calculus (maxima and minima)

The curve is symmetrical about an axis parallel to y axis.

The vertex is the point where

Given:

Differentiating wrt x

Hence, the vertex is

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