Question

What is the vertex of `y= -x^2 + 3`?

Answer 1

The vertex is at `(0,3)`

Explanation:

One way to see this is to convert the given equation into the general "vertex form" for a parabola:
`color(white)("XXX")y=(m)(x-color(red)(a))^2+color(blue)(b)` with vertex at `(color(red)(a),color(blue)(b))`

Since
`color(white)("XXX")y=-x^2+3`
is equivalent to
`color(white)("XXX")y=(-1)(x-color(red)(0))^2+color(blue)(3)`
the vertex is at `(color(red)(0),color(blue)(3))`