What is the vertex of # y= -x^2 + 3#?

1 Answer
Jan 11, 2016

The vertex is at #(0,3)#

Explanation:

One way to see this is to convert the given equation into the general "vertex form" for a parabola:
#color(white)("XXX")y=(m)(x-color(red)(a))^2+color(blue)(b)# with vertex at #(color(red)(a),color(blue)(b))#

Since
#color(white)("XXX")y=-x^2+3#
is equivalent to
#color(white)("XXX")y=(-1)(x-color(red)(0))^2+color(blue)(3)#
the vertex is at #(color(red)(0),color(blue)(3))#