# What is the vertex of  y=-x^2-4x-3?

$\left(- 2 , 1\right)$
Rearrange the expression into the form $y = {\left(x - a\right)}^{2} + b$. The vertex is then $\left(a , b\right)$. a is half the coefficient of x in the original equation.
$y = - \left({x}^{2} + 4 x + 3\right)$
$y = - \left({\left(x + 2\right)}^{2} - 1\right)$
$y = - {\left(x + 2\right)}^{2} + 1$
Vertex is $\left(- 2 , 1\right)$