# What is the vertex of y=x^2+6x+5?

Jan 5, 2016

( -3 , -4)

#### Explanation:

making use of the standard form of a trinomial ie. $a {x}^{2} + b x + c$

for y = ${x}^{2} + 6 x + 5$

a = 1 , b = 6 and c = 5

the x-coordinate of the vertex = - (b/2a)

$\Rightarrow x = - \frac{6}{2}$ = - 3

now substitute this value of x into the equation to obtain corresponding value of y.

$\Rightarrow y = {\left(- 3\right)}^{2} + 6 \left(- 3\right) + 5$ = 9 - 18 + 5 = - 4
graph{x^2+6x+5 [-10, 10, -5, 5]}