What is the vertex of # y= x^2 - 8x-4? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs 1 Answer Nallasivam V Dec 3, 2015 Vertex #=4# Explanation: # y= x^2 - 8x-4# vertex #= (-b)/2=(-(-8))/2=4# Answer link Related questions What are the important features of the graphs of quadratic functions? What do quadratic function graphs look like? How do you find the x intercepts of a quadratic function? How do you determine the vertex and direction when given a quadratic function? How do you determine the range of a quadratic function? What is the domain of quadratic functions? How do you find the maximum or minimum of quadratic functions? How do you graph #y=x^2-2x+3#? How do you know if #y=16-4x^2# opens up or down? How do you find the x-coordinate of the vertex for the graph #4x^2+16x+12=0#? See all questions in Quadratic Functions and Their Graphs Impact of this question 4162 views around the world You can reuse this answer Creative Commons License