# What is the vertical asymptote of (x + 4)/(x^2+x-6)?

Sep 1, 2015

There are two vertical asymptotes: $x = 2$ and $x = - 3$

#### Explanation:

The denominator ${x}^{2} + x - 6$ is $0$ when $x$ is $2$ or $- 3$.

Neither of these values make the numerator equal to $0$, so we cannot reduce (simplify) the fraction.

Therefore, we have vertical asymptotes at $2$ and at $- 3$.

The equations of the lines are $x = 2$ and $x = - 3$.