# What is the volume of 3.50 g of a material with a density of 2.98 g/mL?

$\rho , \text{density"="Mass"/"Volume}$. And $\text{volume}$ $\cong$ $1.2 \cdot m L$
And thus $\frac{\text{Volume"="Mass}}{\rho}$ $=$ $\frac{3.50 \cdot \cancel{g}}{2.98 \cdot \cancel{g} \cdot m {L}^{-} 1}$
And thus $\text{volume}$ $>$ $1.0 \cdot m L$, because $\frac{1}{m {L}^{-} 1}$ $\equiv$ $\text{mL}$. So we know we;ve got the right units for the calculation.