Question

What is the volume of 6 M H2SO4 needed to prepare a 250 mL of 0.35 M H2SO4?

Ca= 40.08
Cl= 35.45
Na=22.99
H=1.01
C=12.01
O=16.00
S=32.07

Answer 1

Well, for a start you always add acid to water....and never the reverse....you need approx. `15*mL` of the conc. acid....

Explanation:

Because when we dilute a substance, the number of moles of solute remain CONSTANT....we can use the expression...

`C_1V_1=C_2V_2="total moles of solute, a CONSTANT"`

And thus `V_1=(C_2V_1)/C_1`...the which clearly has the units of volume. Why?

And so .............

`V_1=(0.35*mol*L^-1xx250*mLxx10^-3*L*mL^-1)/(6.0*mol*L^-1)=??*mL.`