# What is the volume of 8.0 g of water?

About $8$ $m L$; the volume will vary slightly according to temperature.
The density of water, $\rho , {H}_{2} O$ $=$ $1.00$ $g \cdot m {L}^{-} 1$ at standard temperature. If we divide mass by density we get a result in volume: $\frac{m a s s}{\mathrm{de} n s i t y}$, i.e. $\frac{m}{\rho}$ $=$ $\frac{8.00 \cdot \cancel{g}}{1.00 \cdot \cancel{g} \cdot m {L}^{-} 1}$ $=$ $8.00 \cdot {\left(\frac{1}{m L}\right)}^{-} 1$ $=$ $8.0 \cdot m L$.