# What is the volume of a 40 " m"xx20 " m"xx12 " m" room in cubic feet?

Mar 20, 2016

$3.39 \times {10}^{5} {\text{ ft}}^{3}$

#### Explanation:

First, you need the conversion factor of meters to feet:

$1 \text{ m"=3.281 " ft}$

Next, convert each edge of the room:

length = $40 \text{ m"xx(3.281 " ft")/(1 " m")=131 " ft}$

width = $20 \text{ m"xx(3.281 " ft")/(1 " m")=65.6 " ft}$

height = $12 \text{ m"xx(3.281 " ft")/(1 " m")=39.4 " ft}$

Then, find the volume:

volume = length $\times$ width $\times$ height

volume = $131 {\text{ ft"xx65.5 " ft"xx39.4 " ft" = 3.39xx10^5 " ft}}^{3}$