# What is the volume of a container that holds 9.67 moles of oxygen gas at 100°C and 1.30 atm pressure?

$V = \frac{n R T}{P} \cong 228 \cdot L$
$V = \frac{9.67 \cdot m o l \times 0.0821 \frac{L \cdot a t m}{K \cdot m o l} \times 373 K}{1.30 \cdot a t m}$.