Question

What is the volume of one mole of any gas at STP?

Answer 1

`22.4L`

Explanation:

The volume of one mole of an ideal gas at STP can be found as follows:

First, What is STP?

STP is the standard conditions of Temperature and Pressure, where, `T=273K` and `P=1atm`.

Since we are looking for the volume of one mole, then `n=1mol`.

Using the ideal gas law: `PV=nRT` we can find the volume by:

`V=(nRT)/P =(1cancel(mol)xx0.08206(L*cancel(atm))/(cancel(K)*cancel(mol))xx273cancel(K))/(1cancel(atm))=22.4L`

Answer 2

The volume of one mole of a gas is either `"22.414 L"`, or `"22.711 L"`, depending on the pressure used for `"STP"`.

Explanation:

It depends on what values you use for `"STP"`. If you use the values of `"273.15 K"` and `"1 atm"`, the volume of one mole of a gas is `"22.414 L"`.

However, the IUPAC and NIST have updated the values for `"STP"` to `"273.15 K"` and `"10"^5 "Pa"` or `"100 kPa"`. With these values, the volume of one mole of a gas is `"22.711 L"`.

http://en.citizendium.org/wiki/Reference_conditions_of_gas_temperature_and_pressure#Molar_volume_of_a_gas