# What is the volume of one mole of any gas at STP?

Nov 19, 2015

#### Answer:

$22.4 L$

#### Explanation:

The volume of one mole of an ideal gas at STP can be found as follows:

First, What is STP?

STP is the standard conditions of Temperature and Pressure, where, $T = 273 K$ and $P = 1 a t m$.

Since we are looking for the volume of one mole, then $n = 1 m o l$.

Using the ideal gas law: $P V = n R T$ we can find the volume by:

$V = \frac{n R T}{P} = \frac{1 \cancel{m o l} \times 0.08206 \frac{L \cdot \cancel{a t m}}{\cancel{K} \cdot \cancel{m o l}} \times 273 \cancel{K}}{1 \cancel{a t m}} = 22.4 L$

Nov 19, 2015

#### Answer:

The volume of one mole of a gas is either $\text{22.414 L}$, or $\text{22.711 L}$, depending on the pressure used for $\text{STP}$.

#### Explanation:

It depends on what values you use for $\text{STP}$. If you use the values of $\text{273.15 K}$ and $\text{1 atm}$, the volume of one mole of a gas is $\text{22.414 L}$.

However, the IUPAC and NIST have updated the values for $\text{STP}$ to $\text{273.15 K}$ and $\text{10"^5 "Pa}$ or $\text{100 kPa}$. With these values, the volume of one mole of a gas is $\text{22.711 L}$.

http://en.citizendium.org/wiki/Reference_conditions_of_gas_temperature_and_pressure#Molar_volume_of_a_gas