The only equation you need for this type of question is this one (which is the only one I remember!):
#c=nu*lambda#
where #c# is the speed of light, #nu# is the frequency and #lambda# is the wavelength. You can rearrange it anyway you need to. In this case:
#lambda=c/nu=(3.0*10^8m/s)/(1.5*10^13Hz)=2.0*10^-5m=20mum = 20000nm#
(Remember that #Hz# is #1/s#, so you can cancel that in the top and bottom leaving only #m#.)
Red light has a wavelength in the range of #620–750 nm#
(https://en.wikipedia.org/wiki/Visible_spectrum) which is much smaller than the #20000 nm# light above.
Note:
The equation above, #v = nu lambda#, works for any wave, where #v# is the speed of the wave and #nu# and #lambda# are frequency and wavelength respectively. The way I remember it is visual - the #nu# and the #lambda# have complementary shapes - they "fit together" when you look at them. You can also write #v=f lambda#, but that doesn't fit together so nicely.