# What is the x and y intercept for x - 2y = 8?

Aug 15, 2015

$x$-intercept: $\left(8 , 0\right)$
$y$-intercept: $\left(0 , - 4\right)$

#### Explanation:

For a general equation of a line written in point-slope form

$\textcolor{b l u e}{y = m x + b}$

the $x$-intercept can be found by finding the value of $x$ that satisfies the condtiion $y = 0$, and the $y$-intercept can be found by evaluating the function for $x = 0$.

$x - 2 y = 8$

You can rearrange this equation into slope-point form if you want

$- 2 y = - x + 8$

$y = \frac{1}{2} x - 4$

So, for the $x$-intercept, you need

$y = \frac{1}{2} x - 4 = 0$

$\frac{1}{2} x = 4 \implies x = 8$

The $x$-intercept will thus be $\left(8 , 0\right)$.

For the $y$-intercept, you substitute $x = 0$ into the equation

$y = \frac{1}{2} \cdot \left(0\right) - 4$

$y = - 4$

The $y$-intercept will thus be $\left(0 , - 4\right)$.

graph{1/2x - 4 [-14.24, 14.24, -7.12, 7.12]}