What is the x and y intercept for x - 2y = 8?

1 Answer
Aug 15, 2015

Answer:

#x#-intercept: #(8,0)#
#y#-intercept: #(0,-4)#

Explanation:

For a general equation of a line written in point-slope form

#color(blue)(y = mx + b)#

the #x#-intercept can be found by finding the value of #x# that satisfies the condtiion #y=0#, and the #y#-intercept can be found by evaluating the function for #x=0#.

In your case, you have

#x - 2y = 8#

You can rearrange this equation into slope-point form if you want

#-2y = -x + 8#

#y = 1/2x - 4#

So, for the #x#-intercept, you need

#y = 1/2x -4 = 0#

#1/2x = 4 implies x = 8#

The #x#-intercept will thus be #(8, 0)#.

For the #y#-intercept, you substitute #x=0# into the equation

#y = 1/2 * (0) - 4#

#y = -4#

The #y#-intercept will thus be #(0, -4)#.

graph{1/2x - 4 [-14.24, 14.24, -7.12, 7.12]}