What is #(-x^3y^4)(-2x^2y^5)#?

1 Answer
Apr 15, 2016

#=2*x^5*y^9#

Explanation:

The easiest way (not necessarily the quickest) to solve this question is by expanding the equation then simplifying it:
#(-x^3y^4)(-2x^2y^5) = -1*x^3*y^4*-2*x^2*y^5#
By rearranging like terms next to each other:
#=-1*-2*x^3*x^2*y^4*y^5#
Now we can use the rule #a^m*a^n = a^(mn)#, we can simplify it down to:
#=2*x^5*y^9#