What is x if #2/x-3x=-4#?

1 Answer
Mar 7, 2016

Answer:

#(2+-sqrt10)/3#

Explanation:

#2/x-3x=-4#
#or 2-3x^2 = -4x #
#or 3x^2 - 4x - 2 = 0#

which is in the standard quadratic form:
#ax^2 + bx + c = 0#

where b = -4, a = 3, c = -2
Hence, the roots of the equation are given by:
#x = (-b +- sqrt(b^2 - 4ac))/(2a)#
#or x = ((4 +- sqrt(16+24))/6)#
#or x = (4 +- sqrt 40 )/6#
#or x=(2 +- sqrt10)/3#