Basically here you want the value of #x# that makes the left side equal to the right. You could try to guess but is complicated...

You can try instead to isolate #x# on one side (the left, for example) and "read" the result.

Remember that everything that passes through the equal sign has to change sign!

If it was a sum it becomes a subtraction;

if it was a multiplication it becomes a division...and vice versa;

In your case:

#-3/4# is multiplying the bracket, so it goes to the right as a division:

#(x+2)=-1/(-3/4)#

the #2# is a sum so it goes to the right as a subtraction:

#x=-1/(-3/4)-2# now we can rearrange to simplify a bit the right side and write:

#x=-1*(-4/3)-2#

#x=4/3-2#

#x=(4-6)/3=-2/3#

You can now try to substitute this value of #x# into your original equation to see if it satisfies it!!!