What is x if #log_2(x)/4= 2#?

1 Answer
Nov 3, 2015

#x=512#

Explanation:

You have to understand what logs are: they are a way of dealing with numbers that are converted to an index form. In this case we are talking about the number 2 (the base) raised to some power (the index).

Multiply both sides by 4 giving:

#((log_2(x))/4) times 4 = (2) times 4# ....... (1)

The brackets are there only to show you the original parts so that it is obvious what I am doing.

But #" "("something")/4 times 4 -> "something" times 4/4 " and "4/4=1#

So equation (1) becomes:

#log_2(x) = 8# ................. (2)

To write equation (2) in index form we have:

#2^8 = x#

#x=512#