What is #x# in this equation #4(x+1) + 8 = 24#?

1 Answer
Jun 18, 2017

See a solution process below

Explanation:

First, subtract #color(red)(8)# from each side of the equation to isolate the term with parenthesis while keeping the equation balanced:

#4(x + 1) + 8 - color(red)(8) = 24 - color(red)(8)#

#4(x + 1) + 0 = 16#

#4(x + 1) = 16#

Next, divide each side of the equation by #color(red)(4)# to eliminate the parenthesis while keeping the equation balanced:

#(4(x + 1))/color(red)(4) = 16/color(red)(4)#

#(color(red)(cancel(color(black)(4)))(x + 1))/cancel(color(red)(4)) = 4#

#x + 1 = 4#

Now, subtract #color(red)(1)# from each side of the equation to solve for #x# while keeping the equation balanced:

#x + 1 - color(red)(1) = 4 - color(red)(1)#

#x + 0 = 3#

#x = 3#