What kind of solutions does #4/3x^2 - 2x + 3/4 = 0 # have?

1 Answer
Jun 27, 2015

Answer:

#4/3x^2 - 2x +3/4=0#
#color(white)("XXXX")##color(white)("XXXX")##color(white)("XXXX")#has one Real solution

Explanation:

For a quadratic of the form #ax^2+bx+c=0#
the discriminant #Delta = b^2-4ac# indicates the number and type of roots.

#Delta {(>0 rarr "2 Real solutions"), (=0 rarr "1 Real solution"),(<0 rarr "no Real solutions (2 Complex solutions)"):}#

For #4/3x^2 -2x +3/4 = 0#

#Delta = (-2)^2 - 4(4/3)(3/4) = 0#