Question

What kind of solutions does `p^2 - 4p + 4 = 0` have?

Answer 1

`color(indigo)("The given equation has ONE REAL ROOT, " (p = 2)`

Explanation:

`D = b^2 - 4ac`

`p^2 - 4p + 4`

`D = b^2 - 4ac = 4^2 - (4 * 1 * 4) = 16 - 16 = 0`

Hence, `color(indigo)("The given equation has ONE REAL ROOT, " (p = 2)`