# What kind of solutions does p^2 - 4p + 4 = 0 have?

Apr 16, 2018

color(indigo)("The given equation has ONE REAL ROOT, " (p = 2)

#### Explanation:

$D = {b}^{2} - 4 a c$

${p}^{2} - 4 p + 4$

$D = {b}^{2} - 4 a c = {4}^{2} - \left(4 \cdot 1 \cdot 4\right) = 16 - 16 = 0$

Hence, color(indigo)("The given equation has ONE REAL ROOT, " (p = 2)