Question

What mass of aluminium chloride can be obtained when 48g of aluminium is completely reacted with dilute hydrochloric acid?

Answer 1

`393.23` grams (approx.)

Explanation:

The balanced reaction between Elemental Aluminium and Dilute Hydrochloric acid is -->

`2Al + 6HCl = 2AlCl_3 + 3H_2`

So, When `2` moles of Elemental `Al` reacts with Dilute `HCl`, It forms `2` moles of `AlCl_3`.

So, `1` mole of `Al` `rarr` `1` mole of `AlCl_3`

`rArr` `13` grams of `Al` `rarr` `106.5` grams of `AlCl_3`

`rArr` `1` gram of `Al` `rarr` `106.5/13` grams of `AlCl_3`

`rArr` `48` grams of `Al` `rarr` `(106.5 * 48)/13` grams of `AlCl_3` = `393.23` grams of `AlCl_3` (approx.)

Hope this helps.