What mass of anhydrous solute is needed to prepare 0.53 L of 0.146 M K2SO4(aq)?

1 Answer
Junaid Mirza
Mar 23, 2018

#"13.4 g"#

Explanation:

#"Molarity" = "Moles of solute"/"Volume of solution (in litres)"#

#"Moles of solute" = "0.146 M" × "0.53 L" = "0.077 mol"#

Molar mass of #"K"_2"SO"_4 = "174 g/mol"#

Mass of solute #= 0.077 cancel"mol" × "174 g"/cancel"mol" = "13.4 g"#

Related questions
Impact of this question
4691 views around the world
You can reuse this answer
Creative Commons License