What mass of potassium hydroxide is required to react completely with 2.70 g of sulfuric acid to produce potassium sulfate and water?

1 Answer
May 7, 2016

#2KOH + H_2SO_4 rarr K_2SO_4 + 2H_2O#


This problem is a bit unrealistic, as I could not really measure such a mass of sulfuric acid. Realistically, I could take a volume of sulfuric acid of a given concentration, which had an equivalent molar quantity to #(2.70*g)/(98.08*g*mol^-1)# #=# #0.0275*mol#.

Given the equation above, i.e. sulfuric acid is a diacid that requires 2 equiv of base, we require #2xx0.0275*molxx56.11*g*mol^-1=3.09*g#

If I had a #1.00*mol*L^-1# solution of sulfuric acid, what volume would I require for equivalence? Such question would be a lot more reasonable.

As you no doubt realize, the ability to write a stoichiometric equation is absolutely vital to answer the question.