What point does the line of y-3=3(x+1) pass through which is the basis of this equation?

1 Answer
Feb 16, 2018

The equation is based on the point #(-1,3)#.

Explanation:

The form of this equation is point-slope form:

#y-y_1=m(x-x_1)#

where #(x_1,y_1)# is a point on the line and #m# is the line's slope. In our equation:

#y-3=3(x+1)#

The #x_1# is #-1#, and the #y_1# is #3#. This means that the point that the equation is based on the #(-1,3)#.