# What's the derivative of #sqrt[arctan(x)]#?

##### 1 Answer

Nov 24, 2016

#### Explanation:

This can be written as

This is in the form

#d/dxu^(1/2)=1/2u^(-1/2)*u'=1/(2sqrtu)*u'#

So for

#d/dxsqrtarctan(x)=1/(2sqrtarctan(x))*1/(x^2+1)#