What torque would have to be applied to a rod with a length of #4"m"# and a mass of #2"kg"# to change its horizontal spin by a frequency #9"Hz"# over #8"s"#?

1 Answer
Feb 13, 2016

Answer:

Use following formula and calculate

Explanation:

Torque (#tau#) = moment of inertia (I)X angular acceleration (#alpha# )
I = #1/12ML^2# , where mass M =2kg, Length L= 4m
#alpha=(domega)/dt# = #2pi#xrate of change of frequency
= 2x3.14x9/8 rads^-2
pl proceed and get result