What volume does 40.5 g of N2 occupy at STP?

1 Answer
Junaid Mirza
Apr 23, 2018

#"32.48 L"#

Explanation:

Molar mass of #"N"_2 = "28 g/mol"#

Moles of #"40.5 g N"_2# gas#= "40.5 g"/"28 g/mol" = "1.45 mol"#

#"1 mol"# of any gas at #"STP"# occupies #"22.4 L"# of volume.

#"1.45 mol"# of #"N"_2# gas will occupy

#1.45 cancel"mol" × "22.4 L"/(1 cancel"mol") = "32.48 L"#

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