# What volume does 7.54 * 10^25 atoms Ne occupy at STP?

Feb 20, 2016

Simple,
First conver $7.54 \times {10}^{25}$ atoms of Ne to moles

To do this, use the equation
Number of particles = Number of moles x Avogadro's constant

Since what we have to find out here is number of moles, rearrange the equation and solve for number of moles

Number of moles = Number of particles/Avogadro's Constant
$= 7.54 \times {10}^{25} / 6.02 \times {10}^{23}$
$= 125.24$
Thus, there are 125.24 moles in $7.54 \times {10}^{25}$ atoms of Ne

Now, the volume of anything at STP is equal to the number of moles multiplied by 22.4 L

Volume(at STP) = No. of moles x 22.4
$= 125.24 \times 22.4$
$= 2805 L / m o l$
Thus, the volume is 2805 L/mol at STP for neon