# What volume (mL) of a concentrated solution of sodium hydroxide (6.00 M) must be diluted to 200.0 mL to make a 0.880 M solution of sodum hydroxide?

Oct 18, 2016

Approx. $30.0 \cdot m L$
We require a $200.0 \cdot m L$ volume of $0.880 \cdot m o l \cdot {L}^{-} 1$ $N a O H \left(a q\right)$.
$\text{Moles of NaOH} = 200.0 \times {10}^{- 3} L \times 0.880 \cdot m o l \cdot {L}^{-} 1 = 0.1760 \cdot m o l$.
We have $6.00 \cdot m o l \cdot {L}^{-} 1$ $N a O H$ available, and thus $\frac{0.1760 \cdot m o l}{6.00 \cdot m o l \cdot {L}^{-} 1}$ $=$ $0.0293 \cdot L$ of the original solution must be diluted to a $200.0 \cdot m L$ volume.