# What volume of 18.0 M H_2SO_4 is needed to contain 2.45 g H_2SO_4?

May 26, 2016

Under $1.5 \cdot m L$.

#### Explanation:

$\frac{2.45 \cdot g}{98.08 \cdot g \cdot m o {l}^{-} 1}$ $=$ $0.0250 \cdot m o l \text{ sulfuric acid}$.

We have $18.0 \cdot m o l \cdot {L}^{-} 1$ ${H}_{2} S {O}_{4}$ available.

Volume required $=$ $\frac{0.0250 \cdot m o l}{18.0 \cdot m o l \cdot {L}^{-} 1} \times 1000 \cdot m L \cdot {L}^{-} 1$ $=$ ??*mL

PS Have you ever lifted a $2.5 \cdot L$ bottle of conc. sulfuric? Why is it so heavy?