What volume of oxygen is produced at STP when #6.58 times 10^24# molecules of water is decomposed?

1 Answer
Feb 5, 2017

Answer:

Every two molecules of water make for one molecule of oxygen.

Explanation:

#2H_2O->2H_2+O_2#

So there will be #0.5xx6.58xx10^24=3.29xx10^24# #O_2# molecules.

#1mol=6.02xx10^23# particles, so the amount produced is:

#(3.29xx10^24)/(6.02xx10^23)=5.47mol#

At an STP of #273K,1atm# the volume is #22.4L//mol#
(you can look up molar volumes for any other STP, there are lots of STP's)

So the volume of oxygen is #5.47xx22.4=122L#