Question

What volume will 2.0 moles of nitrogen occupy at 720 torr and 20°C?

Answer 1

Approx. `50` `L`.

Explanation:

`V=(nRT)/P` `=` `(2.0*molxx0.0821*L*atm*K^-1*mol^-1xx293*K)/((720*"mm Hg")/(760*"mm Hg"*atm^-1))`

The answer is consistent with the known molar volume under standard laboratory condiitions: `25.4*L` at `1*atm` and `298*K`.