# What volume will 2.0 moles of nitrogen occupy at 720 torr and 20°C?

Approx. $50$ $L$.
$V = \frac{n R T}{P}$ $=$ $\frac{2.0 \cdot m o l \times 0.0821 \cdot L \cdot a t m \cdot {K}^{-} 1 \cdot m o {l}^{-} 1 \times 293 \cdot K}{\left(720 \cdot \text{mm Hg")/(760*"mm Hg} \cdot a t {m}^{-} 1\right)}$
The answer is consistent with the known molar volume under standard laboratory condiitions: $25.4 \cdot L$ at $1 \cdot a t m$ and $298 \cdot K$.