# When 1942 J of heat energy is added to 47.4 g of ethanol, C_2H_6O, the temperature increases by 16.7 °C. What is the molar heat capacity of C_2H_6O?

112 J/(mol °C)
ethanol has MM=46,06 g/mol, so you have $n = \frac{47 , 4 g}{46 , 6 \frac{g}{m o l}} = 1 , 030 m o l$ of ethanol. Since Q = n Cm (Tf-Ti) , the molar heat capacity of ethanol is
 Cm = Q/ (n(Tf-Ti)) = (1942 J)/ (1,030 mol 16,7 °C) = 112 J/(mol °C)