When ball is vertically thrown up with velocity "V" it reaches height "h" why is it that when the velocity is doubled "2V" the height becomes " and not "4h" and not "2h" ??

1 Answer
Feb 19, 2018

Your answer lies in this formula,

#v^2 =u^2 -2gh# (this depicts velocity #v# achieved by a body thrown with initial velocity #u# at height #h#)

If #h# is the maximum height reached by the ball,then at that point #v=0#, so #u^2 =2gh#

See, #u^2 prop h#

So, doubling the initial velocity makes the height reached by a ball to become #4 # times.