Question

When propane `C_3H_8` reacts with oxygen, carbon dioxide and water are produced. If 7.51 grams of propane react with excess oxygen, how many grams of carbon dioxide are formed?

Answer 1

`C_3H_8(g) + 5O_2(g) rarr 3CO_2(g) + 4H_2O(g)`

Approx. `22*g` carbon dioxide will result.

Explanation:

From the equation above, 3 moles of carbon dioxide result from every mole of propane combusted.

We had, `(7.51*g)/(44.1*g*mol^-1)` `=` `?? "moles of propane"`.

So how many moles of carbon dioxide? And what is the mass of this quantity?