# When the sum of four consecutive even integers is divided by 7, the result is 4. How do you find the integers?

$4 , 6 , 8 , 10$ are four consecutive even integers. .
Let the four consecutive even integers are $n , n + 2 , n + 4 , n + 6 \therefore \left(n + n + 2 + n + 4 + n + 6\right) = 7 \cdot 4 \mathmr{and} 4 n + 12 = 28 \mathmr{and} 4 n = 16 \mathmr{and} n = 4 \therefore 4 , 6 , 8 , 10$are four consecutive even integers.[Ans]