# When you draw out this compound, where is the double bond? 3-METHYL HEXENE

Jun 6, 2018

With all these problems you draw out the hydrocarbyl chain FIRST....

#### Explanation:

And so we got $\text{n-hexane...}$

${H}_{3} \stackrel{1}{C} - C {H}_{2} \stackrel{3}{C} {H}_{2} \stackrel{4}{C} {H}_{2} C {H}_{2} \stackrel{6}{C} {H}_{3}$...but you specify $\text{3-hexene} \ldots$...between $\stackrel{3}{C}$ and $\stackrel{4}{C}$, there is an olefinic bond....and hence we got...

${H}_{3} \stackrel{1}{C} - C {H}_{2} \stackrel{3}{C} H = \stackrel{4}{C} H C {H}_{2} \stackrel{6}{C} {H}_{3}$..

And so we got $\text{3-hexene}$, but $\text{3-methylhexene}$ was specified…

${H}_{3} \stackrel{1}{C} - C {H}_{2} \stackrel{3}{C} \left(C {H}_{3}\right) = \stackrel{4}{C} H C {H}_{2} \stackrel{6}{C} {H}_{3}$

,,now this structure will generate TWO geometric isomers. What are they?