When you draw out this compound, where is the double bond? 3-METHYL HEXENE

1 Answer
anor277
Jun 6, 2018

With all these problems you draw out the hydrocarbyl chain FIRST....

Explanation:

And so we got #"n-hexane..."#

#H_3stackrel1C-CH_2stackrel3CH_2stackrel4CH_2CH_2stackrel6CH_3#...but you specify #"3-hexene"...#...between #stackrel3C# and #stackrel4C#, there is an olefinic bond....and hence we got...

#H_3stackrel1C-CH_2stackrel3CH=stackrel4CHCH_2stackrel6CH_3#..

And so we got #"3-hexene"#, but #"3-methylhexene"# was specified…

#H_3stackrel1C-CH_2stackrel3C(CH_3)=stackrel4CHCH_2stackrel6CH_3#

,,now this structure will generate TWO geometric isomers. What are they?

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