Which is the domain and range of #f(x) = -3sqrt (x+2) - 6#?

1 Answer
Jul 17, 2018

Answer:

Domain: #x>=-2 or [-2,oo)#
Range : # f(x) <= -6 or (-oo,-6]#

Explanation:

# f(x)= -3 sqrt(x+2) - 6# . Domain: Possible input value of #x#.

Under root should be #>0 ; f(x)# is undefined at #x+2<0#

#:. x+2>=0 or x >= -2# . Therefore domain is

#x>=-2 or [-2,oo)# . Range: Possible output of #f(x)#

for input #x ; sqrt(x+2)>=0:. f(x) <= (-3*0) -6 :.#

Range : # f(x) <= -6 or (-oo, -6]#

graph{-3 sqrt(x+2) -6 [-40, 40, -20, 20]} [Ans]