Which of the following compounds is/are polar covalent: #H_2O#, #CaCl_2#, #N_2#, #CH_4#, #HNO_3#? How is this determined?

1 Answer
May 24, 2017

Answer:

Molecular polarity is the result of the vector sum of the individual bond dipoles..........

Explanation:

And with ionic species, because the charges are formally SEPARATED, we generally do not speak of polarity. So for #CaCl_2# we speak of an ionic salt.

On the other hand, for #""^(delta+)H-stackrel(delta-)O-H#, #""^(delta+)H-stackrel(delta-)Ostackrel(+)N(=O)(-O^(-))# (the nitrogen is also formally quaternized), there is charge separation, polarity, and thus these are polar covalent molecules.

On the other, other hand, for #N_2#, and #CH_4#, there is NO polarity, no charge separation, and these species are classic non-polar molecules.