# Which of the following radicals are simplified: sqrt63, sqrt44, sqrt73, sqrt48?

Dec 30, 2016

$\sqrt{63}$, $\sqrt{44}$, and $\sqrt{48}$ can be simplified...........

#### Explanation:

$\sqrt{63} = \sqrt{7} \times \sqrt{9} = 3 \sqrt{7}$

$\sqrt{44} = \sqrt{4} \times \sqrt{11} = 2 \sqrt{11}$

$\sqrt{48} = \sqrt{12} \times \sqrt{4} = \sqrt{4} \times \sqrt{3} \times \sqrt{4} = {\sqrt{4}}^{2} \times \sqrt{3} = 4 \sqrt{3}$

On the other hand, $\sqrt{73}$ is the square root of a prime number, and has no factors that are perfect squares.