# Which of the ordered pairs is a solution for the equation 4x - 2y = 8 (0,4), (-2,0) (-2,-4)(0,-4)?

Jun 2, 2016

$\left(0 , 4\right)$

#### Explanation:

You have to check if the ordered pair is true for the given equation
So given $4 x - 2 y = 8$
Firstly re-arrange this to $2 y = 4 x - 8$
which can then be divided by 2 to give
$y = 2 x - 4$
Now check each ordered pair
for $\left(0 , 4\right)$ substitute $x = 4$ into the Rihgt hand Side (RHS) to get $\left(2 \times 4\right) - 4 = 8 - 4 = 4$
So for this pair $y = 4$ and the pair satisfies the equation
Now check $\left(- 2 , 0\right)$ in the same way
When $x = - 2$
RHS = $\left(4 \times - 2\right) - 4 = - 12$ which does not equal LHS = 0
Now check $\left(- 2 , - 4\right)$ the x valie is the same as before, so this does not work either
Lastly check $\left(0 , - 4\right)$ but this does not equal the RHS when $x = 0$ either
So the only solution is $\left(0 , 4\right)$