# Why do larger instruments create lower frequencies than smaller instruments?

Frequency all depends upon vibration produced per second . for lets suppose you have a wire of mas 10 $K g$ and its length is 100 $m$ the and its tension on it let 10 $N$ The frequency produced in given by formula
$\nu = \frac{1}{2 l} \sqrt{\frac{T}{m}}$
'm' is mass per unit length substituting the values we get 0.05$H z$
which is pretty less but on the other hand if we use the wire of much lesser mass say 50$g m$ and keeping all other parameters constant we get 0.77$H z$ which is comparatively much higher .