Why do non-polar solvents favour Sn2 reactions and why do polar solvents favour Sn1 reactions? Please simple ways. Thanks a lot

1 Answer
Write your answer here...
Start with a one sentence answer
Then teach the underlying concepts
Don't copy without citing sources


Write a one sentence answer...



Explain in detail...


I want someone to double check my answer

Describe your changes (optional) 200

anor277 Share
Feb 17, 2018


Well, #S_N1# reactions feature a reactive intermediate...a carbocation....


In an #S_N1# reaction, say of isopropyl halide, the reaction is presumed to proceed thru a carbocationic intermediate....i.e. a bond-breaking rate determining step.

#H_3C-CHXCH_3stackrel"polar solvent, slow step"rarrH_3C-stackrel(+)CHCH_3+X^-#

And the presumed intermediate #H_3C-stackrel(+)CHCH_3# is certainly stabilized by interaction with the solvent....

On the other hand, should isopropyl react with a NUCLEOPHILE, the reaction is presumed to occur by a bond-making mechanism that involves reaction of (say) hydroxide anion at the ipso carbon...

#H_3C-CHXCH_3+HO^(-)stackrel"fast step"rarrH_3C-CH(OH)CH_3+X^-#

And this is a concerted mechanism, that involves no reactive intermediates. Less polar solvents magnify the reactivity of the intermediate...hydroxide, for instance is a more powerful nucleophile in ethanol or ether than it is in water, and the nucleophile is more reactive in the alcoholic/ethereal solvent....of course there is a trade-off in solubility versus reactivity...

I would look in your text for bond making versus bond-breaking reactivity....

Was this helpful? Let the contributor know!