Why is #"C"l^-# a Lewis base?

2 Answers
May 22, 2018

Answer:

#"C"l^-# is a Lewis base because it donates a nonbonding electron pair.

Explanation:

An example of this is #"Co"("NH"_3)_4("C"l)_2^(2+)#. It is a complex ion were chlorine has donated electron pairs to cobalt.

May 22, 2018

Answer:

Because it is FORMALLY an electron-pair donor.

Explanation:

And of course it is a fairly poor Lewis-base. Its conjugate acid #HCl# is a strong #”Bronsted acid”#. Fluoride anion is a stronger Lewis-base. Why should this be so?