# With the Equation 6H2O + 6CO2 --> C6H12O6 + 6O2 How many grams of water are needed to make the above amount of glucose if you start with 88.0g of CO2?

##### 1 Answer

Mar 8, 2018

The question doesn't make much sense as it is so I will show you how to find the amount of glucose, given

#6H_2O + 6CO_2 -> C_6H_12O_6 + 6O_2#

We must convert the carbon dioxide to moles. We know that the molar mass of

#88.0 g * (mol)/(44 g) = 2 mol#

Now we look at our chemical equation's mole ratios. We can see that

#1/3 " mol" * 180 g/"mol" = 60 g #

Therefore,

Hopefully this helps!