Without using Wolfram Alpha, evaluate #log_10(y) = -138.265#? The answer is not #0#.
It's easy to do it in Wolfram Alpha, but how could I simplify it so that it's able to be evaluated on a TI-83 calculator? There's a limit to how large or small the displayed numbers can be.
This is useful, for example, when you evaluate #DeltaS = k_BlnOmega# , the microstates equation for entropy.
It's easy to do it in Wolfram Alpha, but how could I simplify it so that it's able to be evaluated on a TI-83 calculator? There's a limit to how large or small the displayed numbers can be.
This is useful, for example, when you evaluate
1 Answer
Aug 25, 2016
Hm, you know what, it would easier to just evaluate part of it on a calculator, and do the rest of it using factors of
#10^(-138.265) = y#
#=> 10^(-38.265 - 100) = y#
#=> 10^(-38.265)/(10^(100)) = y#
Since
